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10x^2-1+11x=0
a = 10; b = 11; c = -1;
Δ = b2-4ac
Δ = 112-4·10·(-1)
Δ = 161
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(11)-\sqrt{161}}{2*10}=\frac{-11-\sqrt{161}}{20} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(11)+\sqrt{161}}{2*10}=\frac{-11+\sqrt{161}}{20} $
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